Factorise: a ^ 2 - (b + c) ^ 2 . Options (a + b + c)(a - b + c); (a - b + c)(a - b + c) ( a+ b +c)(a-b-c)
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Answer:
Correct option is
A
(a+b)(a+c)
let us rearrange the terms and take a and c as a the common factor
we get
= a
2
+ bc + ab + ac = a
2
+ ab + bc + ac
⇒a(a+b)+c(a+b)=(a+b)(a+c)
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=00000000000000000000000000000000000000000000000000000000000000000000000000a
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