Math, asked by adityadavps8f2021, 1 month ago

Factorise: a ^ 2 - (b + c) ^ 2 . Options (a + b + c)(a - b + c); (a - b + c)(a - b + c) ( a+ b +c)(a-b-c)​

Answers

Answered by PRABEERPATIL
0

Answer:

Correct option is

A

(a+b)(a+c)

let us rearrange the terms and take a and c as a the common factor

we get

= a

2

+ bc + ab + ac = a

2

+ ab + bc + ac

⇒a(a+b)+c(a+b)=(a+b)(a+c)

Answered by Hasitamvats
0

=00000000000000000000000000000000000000000000000000000000000000000000000000a

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