Question

factorise: a^2(b+c)-(b+c)^3​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Solution:

a²(b+c)-(b+c)³

Taking (b+c) common,

= (b+c)[ a²- (b+c)²]

= (b+c){[a+(b+c)][ a-(b+c)]

/* x²-y² = (x+y)(x-y) */

= (b+c)( a+b+c)(a-b-c)

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