Question

factorise:
a^2+bc-ac-b^2​

Answer 1

Answer:

a²+bc-ac-b² = (a-b)(a+b-c)

Step-by-step explanation:

Given a²+bc-ac-b²

Rearranging the terms ,we get

= (a²-b²)+bc-ac

= (a+b)(a-b)+c(b-a)

= (a+b)(a-b)-c(a-b)

= (a-b)(a+b-c)

Therefore,

a²+bc-ac-b² = (a-b)(a+b-c)

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Answer 2

(a - b)[a + b - c]

Step-by-step explanation:

Given:

a² + bc - ac - b²

Find:

Factories.

Computation:

a² + bc - ac - b²

By arranging the equation.

a² - b² - ac + bc

[∵ x² - y² = (x + y)(x - y)]

So,

(a + b)(a - b) - c(a - b)

(a - b)[(a + b) - c]

(a - b)[a + b - c]

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