factorise a^2-x^2-2xy-y^2
Answers
Answered by
4
Hi there !
Given,
To factorise.
a² - x² - 2xy - y²
= a² - (x² + 2xy + y²)
Using the algebraic identity , (a+b)²=a²+2ab+b²,
we have,
= a² - (x + y)²
Here
Let
x = a. b = x + y
So,
Using the identity , x² - b² = (x - b)(x + b)
we have,
a² - x² - 2xy - y² = (a - x - y)(a + x + y). [ Answer]
Given,
To factorise.
a² - x² - 2xy - y²
= a² - (x² + 2xy + y²)
Using the algebraic identity , (a+b)²=a²+2ab+b²,
we have,
= a² - (x + y)²
Here
Let
x = a. b = x + y
So,
Using the identity , x² - b² = (x - b)(x + b)
we have,
a² - x² - 2xy - y² = (a - x - y)(a + x + y). [ Answer]
Answered by
3
Hey!
______________
a^2 - x^2 - 2xy - y^2
a^2 - (x^2 + 2xy + y^2)
We know, (a+b)^2 = a^2 + 2ab + b^2
a^2 - (x+y)^2
Now, let b = x+y
Using identity - a^2 - b^2 = (a+b) (a-b)
Answer - (a-x-y) (a+x+y)
______________
Hope it helps...!!!
______________
a^2 - x^2 - 2xy - y^2
a^2 - (x^2 + 2xy + y^2)
We know, (a+b)^2 = a^2 + 2ab + b^2
a^2 - (x+y)^2
Now, let b = x+y
Using identity - a^2 - b^2 = (a+b) (a-b)
Answer - (a-x-y) (a+x+y)
______________
Hope it helps...!!!
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