Question

Factorise
a) 20
l^2 m+30 a lm​

Answer 1

Answer

We have, 20l

2

m=2×2×5×l×l×m

and, 30alm=3×2×5×a×l×m

The two terms have2,5,l and m as common factors

∴20l

2

m+30alm=(2×2×5×l×l×m)+(3×2×5×a×l×m)=2×5×l×m×(2×l×+3×a)

=10lm(2l+3a)

Explaination

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