factorise (a+2b) (3a+b) - (a+b) (a+2b) +(a+2b)^2
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(a+2b) (3ab+b) -(a+b) (a+2b)+(a+2b)^2=3a^2+8ab+4b^2
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Answer:
3a^2+4b^2+8ab
={a(3a+b)+2b(3a+b)} -{a(a+2b)+b(a+2b)}+{a^2+2ab+2b^2}
solved this we get,
3a^2+4b^2+8ab
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