factorise:- a+2b+a^3+8b3
Answers
Answered by
22
(a+2b)+(a+2b)(a^2-2ab+4b^2)
=(a+2b)(1+a^2-2ab+4b^2)
a^3+b^3=(a+b)(a^2-ab+b^2). since a^3+8b^3=
a^3+(2b)^3
=(a+2b)(1+a^2-2ab+4b^2)
a^3+b^3=(a+b)(a^2-ab+b^2). since a^3+8b^3=
a^3+(2b)^3
Answered by
32
Answer:
a+2b[1+a²-2ab+4b²]
Step-by-step explanation:
a+2b+a³+8b³
a+2b+(a+2b)³-3×a×2b(a+2b) (a³+8b³=(a+2b)³-3ab(a+b)
a+2b[1+(a+2b)²-6ab]
a+2b[1+a²+4b²+4ab-6ab]
a+2b[1+a²-2ab+4b²]
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