factorise a^2b+ab^2-abc-b^2c+axy+bxy
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Answered by
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### HEY FRIEND ###
HERE'S YOUR ANSWER
This is the solution of right side.
after multiplying (a+b+c)(ab+bc+ac) and ignoring -3abc you will get answer like this.
= a2b+abc+a2c+ab2+b2c+abc+abc+bc2+ac2 and that -3abc
= a2b+a2c+ab2+b2+bc2+ac2 +3abc -3abc
= after cancelling +3abc and -3abc you get the above left answer.
HERE'S YOUR ANSWER
This is the solution of right side.
after multiplying (a+b+c)(ab+bc+ac) and ignoring -3abc you will get answer like this.
= a2b+abc+a2c+ab2+b2c+abc+abc+bc2+ac2 and that -3abc
= a2b+a2c+ab2+b2+bc2+ac2 +3abc -3abc
= after cancelling +3abc and -3abc you get the above left answer.
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0
Answer:
hello my lazy people
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