Math, asked by shakshee06, 4 months ago

factorise a^3-1/a^3-2a+2/9​

Answers

Answered by eswarivanjarapu
1

Answer:

Answer:

Step-by-step explanation: Substituting 1/a as b

Taking first term a^3-b^3=(a-b) (a^2+ab+b^2)

Second term -2(a-b)

(a-b) (a^2+ab+b^2)-2(a-b)

a-b is common

So (a-b) (a^2+ab+b^2)-2(1)

Substituting b =1/a

(a-1/a)(a^2+a*1/a+1/a^2)-2

(a-1/a) (a^2+1/a^2+1)-2

(a-1/a) (a^2+1/a^2-1)

This is the ans.

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