factorise a^3-1/a^3-2a+2/9
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Step-by-step explanation: Substituting 1/a as b
Taking first term a^3-b^3=(a-b) (a^2+ab+b^2)
Second term -2(a-b)
(a-b) (a^2+ab+b^2)-2(a-b)
a-b is common
So (a-b) (a^2+ab+b^2)-2(1)
Substituting b =1/a
(a-1/a)(a^2+a*1/a+1/a^2)-2
(a-1/a) (a^2+1/a^2+1)-2
(a-1/a) (a^2+1/a^2-1)
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