Question

factorise a^3-1/a^3-36​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The question is that we have to factorise the given expression .

The expression is

${a}^{3} - \frac{1}{ {a}^{3} } - 36$

take the LCM and equalise the following.

$\frac{( {a}^{3} \times {a}^{3} - 1 - 36 {a}^{3} ) }{ {a}^{3} } \\ \frac{ {a}^{6} - 36 {a}^{3} - 1 }{ {a}^{3} } \\ taking \: quadratic \: equation \\ { ({a}^{2} )}^{4} - (6 {a})^{2} \times a - {1}^{2} \\ \\ { ({a}^{2}) }^{ 4} - {(3a + 3a)}^{2} \times a - {(1)}^{2}$

on factorising we get

${a}^{2} - 3a - 1$

is the one of the factor.

In order to find the another factor see the picture given above

Aa per the result obtained in the picture we get another factor as

$( {a}^{4} + 3 {a}^{3} + 10 {a}^{2} - 3a + 1)$

The final answer is

$\frac{1}{ {a}^{3} } \times ( {a}^{2} - 3a - 1)( {a}^{4} + 3 {a}^{3} + 10 {a}^{2} - 3a + 1)$

# spj2

we can find the similar questions through the link given below

https://brainly.in/question/42129845?referrer=searchResults