Question

factorise :- a^3+1 by using(a+b)^3=a^3+^b^3+3ab(a+b)​

Answer 1

Step-by-step explanation:

a^3-b^3+1+3a.b

Formula :-

x^3+y^3+z^3–3.x.y.z =(x+y+z) (x^2+y^2+z^2-xy-yz-zx).

Question:-

=(a)^3 +(-b)^3 + (1)^3 -3.a.(-b).1

=[a+(-b,)+1] [(a)^2+((- b)^2+(1)^2-a.(- b)-(-b).1- 1.a]

=(a-b+1) (a^2+b^2+1+a.b+b-a) , Answer.

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