Math, asked by brainlyDhruv, 1 year ago

Factorise: (a^3)-(2√2b^3)

Answers

Answered by abhi178
317
(a)³ - (2√2b³)

(a)³ - (√2b)³

we know,

a³ - b³ = (a - b)(a² + ab + b²)

so,

a³ -(√2b)³ = ( a-√2b)(a² + √2²b² + √2ab)

=( a -√2b)(a² + 2b² + √2ab)

hence, ( a -√2b) and ( a² +2b² +√2ab) are the factors of a³ -(2√2b³)
Answered by dhathri123
130
hi friend,

a³-(2√2b³)=a³-(√2b)³

we know that a³-b³=(a-b)(a²+ab+b²)


=(a-√2b)(a²+√2ab+2b²)


I hope this will help u :)







brainlyDhruv: why do we made the '2' to be seprated
dhathri123: to make that in the form of formula
brainlyDhruv: I can't umderstand that..
dhathri123: (√2b)³=2√2b³ so i made it in that way to use the formula
brainlyDhruv: Ok Thanks..!
dhathri123: :)
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