Question

Factorise:
(a-3)^2-(a+3)(a-3)​

Answer 1

$\tt {(a - 3)}^{2} - (a + 3)(a - 3)$

$\tt = > (a - 3){(a - 3) - (a + 3)}$

$\tt = > (a - 3){( \cancel a - 3 - \cancel a + 3)}$

$\tt = > (a - 3){ - 6}$

$= > - 6(a - 3)$

Answer 2

Answer:

\tt {(a - 3)}^{2} - (a + 3)(a - 3)(a−3)

2

−(a+3)(a−3)

\tt = > (a - 3){(a - 3) - (a + 3)}=>(a−3)(a−3)−(a+3)

\tt = > (a - 3){( \cancel a - 3 - \cancel a + 3)}=>(a−3)(

a

−3−

a

+3)

\tt = > (a - 3){ - 6}=>(a−3)−6

= > - 6(a - 3)=>−6(a−3)

Hope it helps||||||||||✌✌✌✌