Question

Factorise a^3 +27b^3+8c^3- 18 abc

Answer 1

a³ + 27b³+ 8c³- 18abc

a³+3b³+2c³-3(a) (3b) (3c)

(a+3b+2c) [(a)² + (3b)² +(2c)² -(a) (3b) - (3b) (2c) - (2c) (a) ]

(a+3b+2c) [a² + 9b² + 4c² - 3ab - 6abc - 2ca]

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Answer 2

Answer:

Step-by-step explanation:

a³ + 27b³+ 8c³- 18abc

a³+3b³+2c³-3(a) (3b) (3c)

(a+3b+2c) [(a)² + (3b)² +(2c)² -(a) (3b) - (3b) (2c) - (2c) (a) ]

(a+3b+2c) [a² + 9b² + 4c² - 3ab - 6abc - 2ca]

(a+3b+2c)^2