Factorise: a 3 +3 root3b3 [It is said as follows (for avoiding confusion): a cube + 3 root 3 b cube]
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a³+3√3b³
⇒(a)³+(√3b)³
⇒(a)³+(√3b)³=(a+√3b){(a²)-a*√3b+(√3b)²}
=(a+√3b)(a²-√3ab+3b²)
⇒(a)³+(√3b)³
⇒(a)³+(√3b)³=(a+√3b){(a²)-a*√3b+(√3b)²}
=(a+√3b)(a²-√3ab+3b²)
samyak15:
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Answer:
(a+√3b) (a²-√3ab+3b²)
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