Question

factorise a^3 - 3a^2b + 3ab^2 -2b^3​

Answer 1

Answer:

a3 + 3a2 b + 3ab2 + b3 - 8 = (a3 + 3a2b + 3ab2 + b3) – 8 = (a + b)3 - 8 = (a + b)3 – (2)3 = (a + b -2) {(a + b)2 + (2)2 + 2(a + b)} = (a + b - 2) (a2 + b2 + 2ab + 4 + 2a + 2a)

Answer 2

solve by substitution method 3p - 2q = 5 and q - 1 = 3p

answer :

P= – 7/3

p= –6

3p -2q = ==> (1)

q-1 =3p==> 3p -- q = (--1 )

3q -- q = (--1 ) ==> 2

equation (1)-(2):

- 1q = 6==> q= ( -- 6 )

putting q=(-6) in eq (2):

p=(-7/3)

hope it helps (•‿•)