factorise a^3-4b^3-64c^3-12^2abc
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hi there this is the answer
Step-by-step explanation:
³ - 12a(a - 4) - 64
= a³ - 12a² + 48a - 64
= a³ - 4a² - 8a² + 32a + 16a - 64
= a²(a - 4) - 8a(a - 4) + 16(a - 4)
= (a - 4)(a² - 8a + 16)
= (a - 4){a² - 4a - 4a + 16}
= (a - 4){a(a - 4) - 4(a - 4)}
= (a - 4)(a - 4)(a - 4)
= (a - 4)³
Therefore the factorisation of a³ - 12a(a - 4) - 64 is (a - 4)³.
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