factorise a 3 + 8 b 3 - 3 + 6 ABC
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Using identity x3+y3+z3−3xyz=(x+y+z)(x2+y2+z2−xy−yz−zx)
Which gives
a3−b3+8c3−6abc=(a−b+2c)(a2+b2+4c2+ab+2bc−2ca)
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