factorise a^3 + b^3 + a + b
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this is your solution
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Step-by-step explanation:
a³ + b³ + a + b
=> (a+b) [( a² + 2ab + b² ) -(a+b)]
= (a +b) [ ( a² + 2ab + b² ) - 1]
= a² + 2ab +b² + 1 ( ans )..
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