Question

Factorise:
a) 36-9x²
b) 9a²+16-24a
need it fast ​

Answer 1

Answer:

1. 9*(2+x)(2-x)
2. $(3a-4)^{2}$

Step-by-step explanation:

a)

36-9x²

=$(6)^{2}-(3x)^{2}$

=(6+3x)(6-3x)  from, $a^{2}-b^{2}=(a+b)(a-b)$

=3*(2+x)3*(2-x)

=9*(2+x)(2-x)

or,

36-9x²

=$9(4-x^{2} )$

=$9(2^{2}-x^{2})$

=9(2+x)(2-x)  from, $a^{2}-b^{2}=(a+b)(a-b)$

b)

9a²+16-24a

=9a²-24a+16

=$(3a)^{2}-2*3a*4+(4)^{2}$

=$(3a-4)^{2}$  from, $(a+b)^{2}=a^{2}+2ab+b^{2}$

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