Factorise
a^4+2a^2b^2+b^4
Answers
Answered by
6
Step-by-step explanation:
Hi Priya
Here's your answer
we know that (x+y)^2=x^2+y^2+2xy
similarly here we can write a^4+2a^2b^2+b^2 as (a^2)^2+(b^2)^2+2a^2b^2
so it can also be written as (a^2+b^2)^2
hence the answer is (a^2+b^2)^2
Hope, it helps.
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Answered by
1
Step-by-step explanation:
a⁴+2a²b²+b²
(a²)²+2(a)²(b)²+(b²)²
substitute aA=a² and B= b²
A² +2AB + B²
(A+B)² = (A+B) (A+B)
using identity,
substitute A=a² and B = b²
a⁴+2a²b²+b⁴ = (a²+b²) (a²+b²)
hence the factorisation of a⁴ + 2a²b²+b² = (a² + b²) (a²+b²)
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