Question

Factorise:a 4 +2a 3 b-2ab 3 -b 4 ..

Answer 1

Solutions 

⇒  Simplify $2a * 3b = 6ab$

$4+6ab-2ab*3-b^4$ 

⇒ Simplify $2a * 3 = 6ab$ 

$4+6ab-6ab-b^4$ 

⇒ Simplify 

$4-b^4$ 

⇒ This fits the form $a^2-b^2$ 
Rewrite it where $a = 2$ and $b = b^2$ 

$2^2-(b^2)^2$ 

⇒ Use Difference of Squares $a^2-b^2=(a+b)(a-b)$ 

$(2+b^2)(2-b^2)$ 

Hence Solved Δ