Question

factorise a^4_a^2 completly with suatable identity

Answer 1

(a^2-a)(a^2+a)
=(a+√a)(a-√a)(a^2+a)
using he identity (a+b)(a-b)

Answer 2

Hey there!
Down here ⏬

Factorise

$a {}^{4} - a {}^{2}$

$using \: the \: equation \: (a - b) {}^{2} = a {}^{2} - 2ab - b {}^{2}$

$(a {}^{2} - a) {}^{2}$

$a = a {}^{2}$
$b = a$

$(a {}^{2}) {}^{2} - 2(a {}^{2})(a) - (a) {}^{2}$

$a {}^{4} - 2a {}^{3} - a {}^{2}$

Hope helped.