Question

factorise a) 4x2 - (1/y)2

b) X3 +8y3 + 6x2y+8xy2​

Answer 1

Answer:

wait I am solving OK done

Answer 2

Step-by-step explanation:

$4 {x}^{2} - \frac{1}{ {y}^{2} } = {(2x)}^{2} - ( { \frac{1}{y} )}^{2} =(2x + \frac{1}{y} )(2x - \frac{1}{y} )$

${x}^{3} + 8 {y}^{3} + 6 {x}^{2}y + 12 {y}^{2} x = ( {x)}^{3} + (2 {y})^{3} + 3 {(x)}^{2} 2y + 3 {(2y)}^{2} x = {(x + 2y)}^{3}$