Math, asked by ysrideviramu, 10 months ago

Factorise
a) 4y2- 12y +9​

Answers

Answered by gargiupadhyay566
103

Answer:

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Answered by pulakmath007
2

\displaystyle \sf{4 {y}^{2} - 12y + 9   } = (2y - 3)(2y - 3)

Given :

\displaystyle \sf{4 {y}^{2} - 12y + 9   }

To find :

To factorise the expression

Formula :

\displaystyle \sf{  {(a - b)}^{2}  = {a}^{2} - 2ab +  {b}^{2}    }

Solution :

Step 1 of 2 :

Write down the given expression

Here the given expression is

\displaystyle \sf{4 {y}^{2} - 12y + 9   }

Step 2 of 2 :

Factorise the expression

\displaystyle \sf{4 {y}^{2} - 12y + 9   }

\displaystyle \sf{ = {(2y)}^{2} - 2 \times 2y \times 3 +  {(3)}^{2}   }

\displaystyle \sf{ =  {(2y - 3)}^{2} }\:  \:  \: \bigg[ \:  \because \:{(a - b)}^{2}  = {a}^{2} - 2ab +  {b}^{2}  \bigg]

\displaystyle \sf{ =  (2y - 3) (2y - 3)}

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