Factorise a^6 - 27b^3 + 64c^3 +36a^2bc
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a^6 - 27b³+64c³ + 36a²bc
= (a²)³ + (-3b)³ + (4c)³ - 3 × a² × 3b × 4c
Using
a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c³-ab-bc-ca)
= {a²+(-3b)+4c}{ (a²)²+ (-3b)² + (4c)² - a²×-3b - (-3b)(4c) - (4c)(a²)
= (a²-3b+4c)(a⁴+ 9b²+16c²+ 3a²b +12bc - 4a²c)
= (a²)³ + (-3b)³ + (4c)³ - 3 × a² × 3b × 4c
Using
a³ + b³ + c³ - 3abc = (a+b+c)(a²+b²+c³-ab-bc-ca)
= {a²+(-3b)+4c}{ (a²)²+ (-3b)² + (4c)² - a²×-3b - (-3b)(4c) - (4c)(a²)
= (a²-3b+4c)(a⁴+ 9b²+16c²+ 3a²b +12bc - 4a²c)
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here is ur answer buddy
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