Question

factorise a^6-7a^3-8

Answer 1

Hey!!! your answer is here!!!!!
a^6-7a³-8
(a³+1)(a³-8)
(a+1)(a²-a+1)(a²+2a+4)


Answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!.....❣

Answer 2

a^3^2-7a^3-8=0
a^3=t
t^2-7t-8=0
t=1/8
a=1 or 2