factorise a^8-a^2b^6
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Answer:
Step-by-step explanation:
a2a6−a2b6
=a2(a6−b6), here a2 is common between the terms
=a2(a3×2−b3×2)
=a2[(a3)2−(b3)2]
This is of the form x2−y2=(x−y)(x+y),where x=a3 and y=b3
=a2(a3−b3)(a3+b3)
Now we factorize (a3−b3) and (a3+b3):
We know that (a3−b3)=(a−b)(a2+ab+b2)
And (a3+b3)=(a+b)(a2−ab+b2)
Then,
a2(a3−b3)(a3+b3)=a2(a−b)(a2+ab+b2)(a+b)(a2−ab+b2)
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