Question

Factorise a^8 - y^8.

Answer 1

$\textbf{ Hello Mate! }$

Refer to attatchment please.

Concept : a^4 + b^4 = (a^2+b^2)^2 - 2a^2b^2

Because, a^4 + b^4 + 2a^2b^2 - 2a^2b^2

And we will get, a^4 + b^4 again.

Morover, 2a^2b^2 can be written as

${( \sqrt{2} ay)}^{2}$

Have great future ahead!