Question

Factorise :
a)
(a-2b)^3 +(2b–3c) ^3+(3c -a)^3​

Answer 1

Answer:

(a - 3c)(a² - 6ab + 12b² + 3ac - 18bc + 9c² - 1)

Answer 2

Answer:

Since, a-2b +2b-3c + 3c- a =0

So, using identity a^3 + b^3 + c^3 =3abc

Hence,

(a-2b)^3 +(2b–3c) ^3+(3c -a)^3​ = 3(a-2b)^3 +(2b–3c) ^3+(3c -a)^3​