Factorise a(a-2b-c)+2bc
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Answer:
a(a-2b-c)+2bc
= a²-2ab-ac+2bc
= a²-ac-2ab+2bc
= a(a-c)-2b(a-c)
= (a-2b)(a-c)
so, (a-2b) and (a-c) are two factors of a(a-2b-c)+2bc
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