Factorise a(a+b-c)-bc
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Step-by-step explanation:
Step-by-step explanation:
Given : Expression a(a+b-c)-bca(a+b−c)−bc
To find : Factories the expression ?
Solution :
First we simplify the expression,
a(a+b-c)-bc=a^2+ab-ac-bca(a+b−c)−bc=a
2
+ab−ac−bc
Take common terms out,
a(a+b-c)-bc=a(a+b)-c(a+b)a(a+b−c)−bc=a(a+b)−c(a+b)
Take common factor out,
a(a+b-c)-bc=(a+b)(a-c)a(a+b−c)−bc=(a+b)(a−c)
Therefore, the factories form is a(a+b-c)-bc=(a+b)(a-c)a(a+b−c)−bc=(a+b)(a−c)
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