factorise a(a + c) - b(b + c)
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Given : a(a+b−c)−bc
We can further write it as
a(a+b−c)−bc=a
2
+ab−ac−bc
By taking the common terms out
a(a+b−c)−bc=a(a+b)−c(a+b)
So we get,
a(a+b−c)−bc =(a+b)(a−c)
We can further write it as
a(a+b−c)−bc=a
2
+ab−ac−bc
By taking the common terms out
a(a+b−c)−bc=a(a+b)−c(a+b)
So we get,
a(a+b−c)−bc =(a+b)(a−c)
Answered by
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Answer:
a²+ac-b²-bc
a²-b²+c(a-b)
(a+b) (a-b) +c(a-b)
(a-b)[(a+b)+c]
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