Question

factorise (a+b)^3+64(a-b)^3​

Answer 1

Answer:

helo guys its your answer

Step-by-step explanation:

(1)64 - a3b3 = (4)3 - (ab)3 = ( 4 - ab )[(4)2 + 4 x ab + (ab)2 ] [ ∵ a3 - b3 = ( a - b )( a2 + ab + b2 )] = ( 4 - ab )( 16 + 4ab +(2)Expanding: (a+b)3−(a−b)3. =(a3+3a2b+3ab2+b3)−(a3−3a2b+3ab2−b3). =6 a2b+2b3.