Question

factorise (a+b)^3-8​

Answer 1

Answer:

$a {}^{3} + b {}^{3} + 3 {a}^{2}b + 3ab {}^{2} - 8$

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Answer 2

${(a + b)}^{ 3} - 8 \\ = {(a + b)}^{3} - {2}^{3} \\ = (a + b - 2)(( {a + b)}^{2} + (a + b).2 + {2}^{2}) \\= (a + b - 2)({a}^{2} +2ab+b^{2}+2a +2b +4)$

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