Question

factorise (a+b)^3-a-b​

Answer 1

Answer:

(a+b)³-a-b=(a+b)(a+b+1)(a+b-1)

Explanation:

Factorisation of (a+b)³-a-b

= (a+b)(a+b)²-1(a+b)

Take (a+b) common, we get

= (a+b)[(a+b)²-1]

= (a+b)[(a+b)²-1²]

= (a+b)[(a+b)+1][(a+b)-1]

/* By algebraic identity */

\boxed {x^{2}-y^{2} = (x+y)(x-y)}x2−y2=(x+y)(x−y)

= (a+b)(a+b+1)(a+b-1)

Therefore,

(a+b)³-a-b=(a+b)(a+b+1)(a+b-1)

hope you understood