Question

Factorise (a+b)^3-a-b​

Answer 1

Answer:

(a+b)³-a-b=(a+b)(a+b+1)(a+b-1)

Explanation

Factorisation of (a+b)³-a-b

= (a+b)(a+b)²-1(a+b)

Take (a+b) common, we get

= (a+b)[(a+b)²-1]

= (a+b)[(a+b)²-1²]

= (a+b)[(a+b)+1][(a+b)-1]

/* By algebraic identity */

=(x+y)(x−y)

= (a+b)(a+b+1)(a+b-1)

Therefore,

(a+b)³-a-b=(a+b)(a+b+1)(a+b-1)

Answer 2

Step-by-step explanation:

Hope it's helpful............