factorise: (a+b)³-a-b
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( a + b )³ - a - b = ( a + b )³ - ( a + b ) taking (a + b) in common = (a + b) { ( a + b )² - 1 } = ( a + b) (a² + b² + 2ab-1) [(a + b)² = a² + b² + 2ab]
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