Factorise (a+b)^3 -a-b
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(a+b)^3-a-bWe know the identity a
3
−b
3
=(a−b)(a
2
+b
2
+ab)
Using the above identity, the equation 1−x
3
can be factorised as follows:
a
3
−2
2
b
3
=(a)
3
−(
2
b)
3
=(a−
2
b)[(a)
2
+(
2
b)
2
+(a×
2
b)]=(a−
2
b)(a
2
+2b
2
+
2
ab)
Hence, a
3
−2
2
b
3
=(a−
2
b)(a
2
+2b
2
+
2
ab)
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