factorise : (a-b)^3+(b-c)^3+(c-a)^3
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Answered by
2
Answer:
If X+Y+Z=0
Then X³+Y³+Z³=3XYZ
Here X=(a-b);Y=(b-c);Z=(c-a).
X+Y+Z=a-b+b-c+c-a
X+Y+Z=0
THEN ;-
(a-b)³+(b-c)³+(c-a)³=3(a-b)(b-c)(c-a)
=3[abc-a²b-ac²+a²c-b²c+ab²-abc+bc²]
=3[a²c-a²b-ac²-bc²+ab²-b²c]
=3[a²(c-b)+c²(b-a)+b²(a-c)]
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Answered by
0
If X+Y+Z=0
Then X³+Y³+Z³=3XYZ
Here X=(a-b);Y=(b-c);Z=(c-a).
X+Y+Z=a-b+b-c+c-a
X+Y+Z=0
THEN ;-
(a-b)³+(b-c)³+(c-a)³=3(a-b)(b-c)(c-a)
=3[abc-a²b-ac²+a²c-b²c+ab²-abc+bc²]
=3[a²c-a²b-ac²-bc²+ab²-b²c]
=3[a²(c-b)+c²(b-a)+b²(a-c)]
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