Math, asked by Abhishek6941, 8 months ago

factorise : (a-b)^3+(b-c)^3+(c-a)^3

Answers

Answered by advocatedmdesai
2

Answer:

If X+Y+Z=0

Then X³+Y³+Z³=3XYZ

Here X=(a-b);Y=(b-c);Z=(c-a).

X+Y+Z=a-b+b-c+c-a

X+Y+Z=0

THEN ;-

(a-b)³+(b-c)³+(c-a)³=3(a-b)(b-c)(c-a)

=3[abc-a²b-ac²+a²c-b²c+ab²-abc+bc²]

=3[a²c-a²b-ac²-bc²+ab²-b²c]

=3[a²(c-b)+c²(b-a)+b²(a-c)]

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Answered by pujithk
0

If X+Y+Z=0

Then X³+Y³+Z³=3XYZ

Here X=(a-b);Y=(b-c);Z=(c-a).

X+Y+Z=a-b+b-c+c-a

X+Y+Z=0

THEN ;-

(a-b)³+(b-c)³+(c-a)³=3(a-b)(b-c)(c-a)

=3[abc-a²b-ac²+a²c-b²c+ab²-abc+bc²]

=3[a²c-a²b-ac²-bc²+ab²-b²c]

=3[a²(c-b)+c²(b-a)+b²(a-c)]

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