Question

Factorise: (a – b)3 + (b – c)3 + (c – a)3​

Answer 1

Answer:

We know that if

a+b+c=0 then

$a {}^{3} + b {}^{3} + c {}^{3} = 3abc$

$now \:( a -b ) + (b - c) + (c -a ) = 0 \\ therefore( a- b) {}^{3} + ( b- c) {}^{3} + (c - a) {}^{3} = 3(a - b)(b -c )(c - a)$

Step-by-step explanation:

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Answer 2

Answer:

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