Math, asked by richajain55, 8 months ago

Factorise: (a-b)^3+(b-c)^3+(c-a)^3​

Answers

Answered by sani0912
0

3a²(c-b) + 3b²(a-c) +3c²(b-a)

Step-by-step explanation:

  • (a−b)³+(b−c)³+(c−a)³
  • =(a³−3a²b+3ab²−b³)+(b³−3b²c+3bc²−c³) + (c³−3c²a+3ca²−a³)
  • =-3a²b+3ab²-3b²c+3bc²-3c²a+3ca²
  • = 3a²(c-b) + 3b²(a-c) +3c²(b-a)

I hope that my answer being helpful for you ✔️

Answered by prajwalxoxo17
0

Step-by-step explanation:

3a²(c-b) + 3b²(a-c) +3c²(b-a)

Step-by-step explanation:

(a−b)³+(b−c)³+(c−a)³

=(a³−3a²b+3ab²−b³)+(b³−3b²c+3bc²−c³) + (c³−3c²a+3ca²−a³)

=-3a²b+3ab²-3b²c+3bc²-3c²a+3ca²

= 3a²(c-b) + 3b²(a-c) +3c²(b-a)

I hope that my answer being helpful for you ✔️

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