Factorise: (a-b)^3+(b-c)^3+(c-a)^3
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Answered by
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3a²(c-b) + 3b²(a-c) +3c²(b-a)
Step-by-step explanation:
- (a−b)³+(b−c)³+(c−a)³
- =(a³−3a²b+3ab²−b³)+(b³−3b²c+3bc²−c³) + (c³−3c²a+3ca²−a³)
- =-3a²b+3ab²-3b²c+3bc²-3c²a+3ca²
- = 3a²(c-b) + 3b²(a-c) +3c²(b-a)
I hope that my answer being helpful for you ✔️
Answered by
0
Step-by-step explanation:
3a²(c-b) + 3b²(a-c) +3c²(b-a)
Step-by-step explanation:
(a−b)³+(b−c)³+(c−a)³
=(a³−3a²b+3ab²−b³)+(b³−3b²c+3bc²−c³) + (c³−3c²a+3ca²−a³)
=-3a²b+3ab²-3b²c+3bc²-3c²a+3ca²
= 3a²(c-b) + 3b²(a-c) +3c²(b-a)
I hope that my answer being helpful for you ✔️
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