Question

factorise (a/b)^3+(b/c)^3+(c/a)^3-3

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Answer 1

Answer:

given that,

(a+b)^3+(b+c)^3+(c+)^3-3

=a^3+3×a^2×b+3×a×b^2+b^3+b^3+3×b^2×c+3×b×c^2+c^3+c^3+3×c^2×a+3×c×a^2+a^3

=2a^3+2b^3+2c^3+3b (a^2+c^2)+3b^2 (a+c)+3ac (a+c)-3

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