Question

factorise:-(a-b)³+(b-c)³+(c-a)³ ​

Answer 1

Answer:

Let x=a-b, y=b-c and z=c-a

So, the expression becomes x³+y³+z³

Since x+y+z=0, therefore, the answer comes to be 3xyz

∴ (a-b)³+(b-c)³+(c-a)³ = 3(a-b)(b-c)(c-a)