factorise (a-b)3 +(b-c)3+(c-a)3
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Hello!
= (a - b) 3 + (b - c) 3 + (c - a) 3
= 3a - 3b + [3b - 3c] + [3c - 3a]
= 3a - 3b + 3b - 3c + 3c - 3a
= 0
I hope it helped.
Thank You!
= (a - b) 3 + (b - c) 3 + (c - a) 3
= 3a - 3b + [3b - 3c] + [3c - 3a]
= 3a - 3b + 3b - 3c + 3c - 3a
= 0
I hope it helped.
Thank You!
mptiwari:
thanks for helping me
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