Question

Factorise: a – b – a2 – b2.

Answer 1

a−b−a2+b2=(a−b)−(a2−b2)

                            =(a−b)−(a−b)(a+b)

                            =(a−b)[1−(a+b)]

$\sf a−b−a2+b2=(a−b)−(a2−b2)</p><p>                            \sf  \\ \sf =(a−b)−(a−b)(a+b)</p><p>             \\ \sf =(a−b)[1−(a+b)]</p><p></p><p>$

Answer 2

${ \fbox{ \fbox{ \fbox{ \fbox {\fbox{\fbox{ \red{hello}}}}}}}}$

Given polynomial is

=a−b−a²+b²=(a-b)-(a²-b²)

=(a−b)−(a−b)(a+b)

=(a−b)[1−(a+b)]