Question

factorise a-b-a3+b3​

Answer 1

Answer:

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Step-by-step explanation:

=(a-b)-(a^3-b^3)

=(a-b)-(a-b)(a^2+ab+b^2)

=[(a-b)(1-a^2+ab+b^2)]

Answer 2

Factorised form is $(a-b)[1-a^2-b^2-ab]$

Step-by-step explanation:

Since we have given that

$a-b-a^3+b^3$

We need to factorise the above expression:

$(a-b)-(a^3-b^3)\\\\=(a-b)-[(a-b)(a^2+b^2+ab)]\\\\=(a-b)[1-(a^2+b^2+ab)]\\\\=(a-b)[1-a^2-b^2-ab]$

Hence, factorised form is $(a-b)[1-a^2-b^2-ab]$

# learn more:

A3+b3+a+b factorise

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