Question

factorise : a(b-c)^2-d(c-b)​

Answer 1

Answer:

The answer will be (b - c){a(b - c) + d}.

Step-by-step explanation:

We have given;

                = a(b-c)^2-d(c-b)​

Now, break it into simplest form;

Hence,           = a(b - c)^2 - dc + db;

                      = a(b - c)^2 + db -dc;

                      = a(b - c)^2 + db -dc;

                      = a(b - c)^2 + d(b - c);

Now, (b - c) as common term;

    Hence,      = (b - c){a(b - c) + d};

Hence, this is our factorize form.

That's all.

Answer 2

Answer:

The answer will be (b-c){a(b-c)+d}

Step-by-step explanation:

We have given

= a(b-c)^2-d(c-b)

Now, break it into simplest form;

Hence, = a(b-c)^2-dc+db;

= a(b-c)^2+db-dc;

= a(b-c)^2+db-dc;

= a(b-c)^2+d(b-c);

Now, (b-c) as common term

Hence, =(b-c){a(b-c)+d};

Hence, this is our factorise form.