Factorise (a+b+c)³-a³-b³-c³
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5
Solution:-
given by :-
(a+b+c)³-a³-b³-c³
= a³+b³+c³+3(a+b)(b+c)(c+a)- a³-b³-c³
=[ 3(a+b)(b+c)(c+a)]ans
given by :-
(a+b+c)³-a³-b³-c³
= a³+b³+c³+3(a+b)(b+c)(c+a)- a³-b³-c³
=[ 3(a+b)(b+c)(c+a)]ans
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