Question

Factorise: a(b-c) - d(c-b)​

Answer 1

e have given;

= a(b-c)^2-d(c-b)

Now, break it into simplest form;

Hence, = a(b - c)^2 - dc + db;

= a(b - c)^2 + db -dc;

= a(b - c)^2 + db -dc;

= a(b - c)^2 + d(b - c);

Now, (b - c) as common term;

Hence, = (b - c){a(b - c) + d};

Hence, this is our factorize form.

Answer 2

Answer:

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